0=12x^2-63x^2+36

Solution for 0=12x^2-63x^2+36 equation:

0=12x^2-63x^2+36

We move all terms to the left:

0-(12x^2-63x^2+36)=0

We add all the numbers together, and all the variables

-(12x^2-63x^2+36)=0

We get rid of parentheses

-12x^2+63x^2-36=0

We add all the numbers together, and all the variables

51x^2-36=0

a = 51; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·51·(-36)
Δ = 7344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7344}=\sqrt{144*51}=\sqrt{144}*\sqrt{51}=12\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{51}}{2*51}=\frac{0-12\sqrt{51}}{102}
=-\frac{12\sqrt{51}}{102}
=-\frac{2\sqrt{51}}{17}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{51}}{2*51}=\frac{0+12\sqrt{51}}{102}
=\frac{12\sqrt{51}}{102}
=\frac{2\sqrt{51}}{17}
$